View Full Version : How to quit properly a program?
I have a simple question but i can't find a answer : how to quit properly a program without shutting down or rebooting.
I just want to quit a a program without doing cwn_driver_sys_pwr_control(CWN_VAL_PWR_REBOOT);
Is "cwn_driver_exit();" the solution to my problem? Why this function is not use in the sample program giver with the SDK?
It seems COWON intended this to be the "right" way to quit a program, probably because this way you can avoid leaving the O2 in a dirty state (haven't tried to see what exactly can go wrong).
If you really want to get back directly to the UI, you will have to:
1. Make sure you exit from your application with status 1 (either return 1; in main() or exit(1);) and that devices are un-initialized properly (call cwn_driver_exit(), close any open files, free allocated memory, etc. - although linux usually takes care of this stuff, the embedded version used *may* lack some functionality in this regard, it's better to be safe).
2. Add the characters "CWN_EXTERN_WATERMARK_GENERIC" to the end of your app's executable (open the NOTEPAD/CALCULATOR apps in a hex editor to see what I mean). I simply used:
echo -n CWN_EXTERN_WATERMARK_GENERIC >> $YOURAPP.o2
Thanks it worked well.
When i run my program (compile for linux) with valgrind ( a memory check), it finds a memory leak of about 160 bytes. It is maybe for this, COWON says to exit the program by rebooting or shutting down.
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